Question

Помогите решить .
3x+1= Корень из 1-x

Answer 1

(3x+1)²=1-x
9x²+6x+1-1+x=0
9x²+7x=0
x(9x+7)=0
x=0 или 9x+7=0
              x= -7/9

Answer 2

$[tex]3x+1= \sqrt{1-x} \\ \\(3x+1) ^{2} =1-x\\3x+1 \geq 0\\\\(3x+1) ^{2} =1-x\\9 x^{2} +1+6x=1-x\\9 x^{2} +1+6x-1+x=0\\9 x^{2} +7x=0\\ x(9x+7)=0\\x=0\\9x=-7\\x=- \frac{7}{9}$

$3x+1 \geq 0\\3x \geq -1\\x \geq - \frac{1}{3} \\\\\\x=- \frac{7}{9} \\x=0$