Question

Z'x, Z'y : Z=Ln x+ 7y^2

Answer 1

$z`_x=(lnx+7y ^{2})`_x=(lnx)`_x+7(y ^{2})`_x= \frac{1}{x} +7\cdot0= \frac{1}{x} \\ \\ z`_y=(lnx+7y ^{2})`_y=(lnx)`_y+7(y ^{2})`_y= 0 +7\cdot 2y= 14y$