Question

Вычислить а) 16^1/4*25^1/2 б) (1/27*125^-1)^-1/3

Answer 1

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Answer 2

$1)16 ^{ \frac{1}{4} } *25 ^{ \frac{1}{2} } = \sqrt[4]{16} * \sqrt[2]{25} =2*5=10\\\\2) (\frac{1}{27} *125 ^{-1} ) ^{- \frac{1}{3} } =(27*125) ^{ \frac{1}{3} }= \sqrt[]{27*125} =3*5=15$