Ответы
Ответ дал:
1
Получится вот так :)
Приложения:
![](https://st.uroker.com/files/663/663df832319231a38bae0555bd8c75bf.jpg)
Ответ дал:
1
Используем свойства степеней ![x^m \cdot x^n= x^{m+n}; \ \ \frac{x^m}{x^n}=x^{m-n}; \ \ (x^n)^m=x^{n \cdot m} x^m \cdot x^n= x^{m+n}; \ \ \frac{x^m}{x^n}=x^{m-n}; \ \ (x^n)^m=x^{n \cdot m}](https://tex.z-dn.net/?f=x%5Em+%5Ccdot+x%5En%3D+x%5E%7Bm%2Bn%7D%3B+%5C+%5C++%5Cfrac%7Bx%5Em%7D%7Bx%5En%7D%3Dx%5E%7Bm-n%7D%3B+%5C+%5C+%28x%5En%29%5Em%3Dx%5E%7Bn+%5Ccdot+m%7D)
![\frac{(b^{\frac{7}{5}}-b^{-\frac{3}{5}})\cdot b^{\frac{3}{5}}}{b^{\frac{1}{3}}\cdot (b^{\frac{2}{3}}+b^{-\frac{1}{3}})}=\frac{b^{\frac{7}{5}}-b^{-\frac{3}{5}}}{b^{\frac{2}{3}}+b^{-\frac{1}{3}}} \cdot b^{\frac{3}{5}-\frac{1}{3}}=\frac{b^{\frac{7}{5}}-b^{-\frac{3}{5}}}{b^{\frac{2}{3}}+b^{-\frac{1}{3}}} \cdot b^{\frac{4}{15}}=\frac{b^{(\frac{7}{5} + \frac{4}{15})}-b^{(-\frac{3}{5}+ \frac{4}{15})}}{b^{\frac{2}{3}}+b^{-\frac{1}{3}}} \frac{(b^{\frac{7}{5}}-b^{-\frac{3}{5}})\cdot b^{\frac{3}{5}}}{b^{\frac{1}{3}}\cdot (b^{\frac{2}{3}}+b^{-\frac{1}{3}})}=\frac{b^{\frac{7}{5}}-b^{-\frac{3}{5}}}{b^{\frac{2}{3}}+b^{-\frac{1}{3}}} \cdot b^{\frac{3}{5}-\frac{1}{3}}=\frac{b^{\frac{7}{5}}-b^{-\frac{3}{5}}}{b^{\frac{2}{3}}+b^{-\frac{1}{3}}} \cdot b^{\frac{4}{15}}=\frac{b^{(\frac{7}{5} + \frac{4}{15})}-b^{(-\frac{3}{5}+ \frac{4}{15})}}{b^{\frac{2}{3}}+b^{-\frac{1}{3}}}](https://tex.z-dn.net/?f=%5Cfrac%7B%28b%5E%7B%5Cfrac%7B7%7D%7B5%7D%7D-b%5E%7B-%5Cfrac%7B3%7D%7B5%7D%7D%29%5Ccdot+b%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D%7D%7Bb%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Ccdot+%28b%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%2Bb%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%29%7D%3D%5Cfrac%7Bb%5E%7B%5Cfrac%7B7%7D%7B5%7D%7D-b%5E%7B-%5Cfrac%7B3%7D%7B5%7D%7D%7D%7Bb%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%2Bb%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%7D+%5Ccdot+b%5E%7B%5Cfrac%7B3%7D%7B5%7D-%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Cfrac%7Bb%5E%7B%5Cfrac%7B7%7D%7B5%7D%7D-b%5E%7B-%5Cfrac%7B3%7D%7B5%7D%7D%7D%7Bb%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%2Bb%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%7D+%5Ccdot+b%5E%7B%5Cfrac%7B4%7D%7B15%7D%7D%3D%5Cfrac%7Bb%5E%7B%28%5Cfrac%7B7%7D%7B5%7D+%2B+%5Cfrac%7B4%7D%7B15%7D%29%7D-b%5E%7B%28-%5Cfrac%7B3%7D%7B5%7D%2B+%5Cfrac%7B4%7D%7B15%7D%29%7D%7D%7Bb%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%2Bb%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%7D)
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