Question

10a+b/b^2-4a^2+ 4a+2b/ b^2 + 4ab+4a^2. При a=0.25; b=4.5

Answer 1

(10a+b)/(b-2a)(b+2a) +2(2a+b)/(b+2a)²=(10a+b)/(b-2a)(b+2a) +2/(b+2a)=
=(10a+b+2b-4a)/(b²-4a²)=(3b+6a)/(b²-4a²)=3(b+2a)/(b-2a)(b+2a)=3/(b-2a)
a=0.25  b=4,5    3/(4,5-0,5)=3/4=0,75