Question

Решите,пожалуйста.Только первый столбец.

Answer 1

1) a⁻⁶ × a⁷/ a⁻³ = a/ a⁻³ = a/1 ÷ 1/a³ = a × a³ = a⁴

2) ( - 2a/3b⁻³)⁻² (a⁻²/4b⁵)⁻¹ = (2⁻²a⁻²/3⁻²b⁶)(a²/4⁻¹b⁻⁵) = 2⁻²a⁻² × a²/3⁻² ×4⁻¹b⁻⁵b⁶ = 2⁻²a°/3⁻² × 4⁻¹b = 3² ×4¹a°/2²b = 9×4/4b = 36/4b = 9/b