Question

Добра, прошу вашей помощи.

Answer 1

$(1- \frac{1}{4} )(1- \frac{1}{9} )*...*(1- \frac{1}{225} )=$$(1- \frac{1}{2} )(1+ \frac{1}{2} )(1- \frac{1}{3} )(1+ \frac{1}{3} )*...*(1- \frac{1}{15} )(1+ \frac{1}{15} )=$$\frac{1}{2}* \frac{3}{2} * \frac{2}{3} * \frac{4}{3} *...* \frac{14}{15} * \frac{16}{15}= \frac{1}{2} * \frac{16}{15} = \frac{8}{15}$