Question

Разложить на множество: 5ax^2-10ax-bx+2b-x+2

Answer 1

$5ax^2-10ax-bx+2b-x+2=(5ax^2-10ax)-(bx-2b)-(x-2)=$$5ax(x-2)-b(x-2)-(x-2)=(x-2)(5ax-b-1)$

Answer 2

(5ax^2-10ax)-(bx-2b)-(x-2)=5ax(x-2)-b(x-2)-(x-2)=(x-2)(5ax-b-1)