Question

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1751dde1f2130893efffb9ac8e73a1af.docx

Answer 1

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Answer 2

$\frac{x}{0,1 : 0,05 : 90 + 0,(2)}=\frac{14\frac{7}{4}}{\frac{25}{2} - \frac{184}{15}}; \\ \\ \frac{x}{\frac{1}{10} \cdot 20 \cdot \frac{1}{ 90} + \frac{2}{9}}=\frac{\frac{63}{4}}{\frac{375-368}{30}}; \\ \\ \frac{x}{\frac{1}{ 45} + \frac{2}{9}}=\frac{30 \cdot 63}{7 \cdot 4}; \\ \\ \frac{x}{\frac{11}{ 45} }=\frac{15 \cdot 9}{2}; \\ \\ \frac{45x}{11}=\frac{135}{2}; \\ \\ 90x=11 \cdot 135; \ \ x= \frac{11 \cdot 135}{90}=\frac{11 \cdot 15}{10}=\frac{165}{10}=16,5$


$\frac{(\frac{2}{3} + \frac{131}{1000}) \cdot 4}{\frac{88541}{900000} : \frac{925}{10000}}=\frac{\frac{4 \cdot (2000+ 393)}{3000}}{\frac{88541 \cdot 10000}{900000 \cdot 925}} =\frac{9572 \cdot 90 \cdot 925}{3000 \cdot 88541}=\frac{9572 \cdot 3 \cdot 925}{100 \cdot 88541}=\frac{9572 \cdot 3 \cdot 37}{4 \cdot 88541}=\frac{9572 \cdot 3}{4 \cdot 2393}=\\ \\ =\frac{9572 \cdot 3}{4 \cdot 2393}=\frac{4 \cdot 3}{4 }=3$


$\frac{0,9 + \frac{3}{5} + \frac{ 2087}{4950} + \frac{1271}{9900}}{\frac{128}{1000} \cdot \frac{25}{4} - \frac{345}{10000} : \frac{12}{100}}= \frac{\frac{9+6}{10} + \frac{4174+1271 }{9900}}{\frac{32}{40} - \frac{69 \cdot 100}{2000 \cdot 12}} = \frac{\frac{3}{2}+ \frac{121}{220}}{\frac{4}{5}- \frac{69}{20 \cdot 12}}=\frac{\frac{330+121}{220}}{\frac{192-69}{240}}=\frac{ 451 \cdot 240}{123 \cdot 220}=\\\\= \frac{451 \cdot 12}{123 \cdot 11}= \frac {12}{3}=4$


$\frac{\frac{1001}{1200} + \frac{77}{450}}{\frac{1001}{1200} - \frac{77}{450}} + \frac{\frac{77}{90}+ \frac{1}{6}}{\frac{77}{90}- \frac{1}{6}} = \frac{3003 + 616}{3003-616}+ \frac{77+15}{77-15}=\frac{3619}{2387}+ \frac{92}{62}=\frac{517}{341}+ \frac{46}{31}= \\ \\ =\frac{517 + 506}{341}=\frac{1023}{341}=\frac{93}{31}=3$


$\frac{(181 - 61) \cdot (181+61)}{(319 - 209) \cdot (319+209)}= \frac{120 \cdot 242}{110 \cdot 528}= \frac{12 \cdot 242}{11 \cdot 528}= \frac{22}{ 44}= \frac{1}{2}$