Question

решить уравнение ((7/9-47/72):1.25+(6/7-17/28):(0,358-0,108)*1,6-19/25

Answer 1

$=(\frac{7}{9}-\frac{47}{72}) : \frac{5}{4} + (\frac{6}{7} -\frac{17}{28}): \frac{1}{4} \cdot \frac{16}{10} -\frac{19}{25}=\frac{56-47}{72} \cdot \frac{4}{5} + \frac{24-17}{28} \cdot 4 \cdot \frac{8}{5} - \frac{19}{25}\\ \\ = \frac{9 \cdot 4}{72 \cdot 5} + \frac{7 \cdot 4 \cdot 8}{28 \cdot 5} - \frac{19}{25}=\frac{4}{8 \cdot 5} + \frac{8}{5} - \frac{19}{25}=\frac{1}{10}+ \frac{8}{5} - \frac{19}{25}=\frac{5 +80-38}{50}= \frac{47}{50}=\\ \\ = 0,94$