Question

Помогите решить $\frac{4}{x^2+6x+9} - \frac{6}{9-x^2} = \frac{1}{x-3}$

Answer 1

4/(x+3)²+6/(x-3)(x+3)-1/(x-3)=0
x≠3 U x≠-3
4(x-3)+6(x+3)-1*(x+3)²=0
4x-12+6x+18-x²-6x-9=0
x²-4x+3=0
x1+x2=4 U x1*x2=3
x1=1
x2=3 не удов усл