Question

помогите расписать примеры
(2x-3)^2-(2x+1)*(2x-5)=3x-14
(x+4)*(x-4)-(2x-3)^2=-3x*(x+1)-22

Answer 1

1) 4х² - 12х +9 - 4х² +10х -2х +5 = 3х - 14
     4х² - 12х +9 - 4х² +10х -2х +5 - 3х + 14 = 0
-7х = -28
х = 4
2) х² - 16 - 4х² +12х -9 = -3х² -3х -22
12х +3х = 16 +9 -22
18х = 3
х = 3/18
х = 1/6
     

Answer 2

$1)(2x-3)^2-(2x+1)(2x-5)=3x-14 \\ 4 x^{2} +9-12x-(4 x^{2} -10x+2x-5)=3x-14 \\ 4 x^{2} +9-12x-(4 x^{2} -8x-5)=3x-14 \\ 4 x^{2} +9-12x-4 x^{2} +8x+5-3x=-14 \\ -12x+8x-3x=-14-9-5 \\ -7x=-28\\x=4$



$2)(x+4)(x-4)-(2x-3) ^{2} =-3x(x+1)-22 \\ x^{2} -16-(4 x^{2} +9-12x)=-3 x^{2} -3x-22 \\ x^{2} -16-4 x^{2} -9+12x+3 x^{2} +3x=-22 \\ 12x+3x=-22+16+9 \\ 15x=3\\x= \frac{3}{15} \\ \\ x=0.2$