Question

Помогите! Очень надо!!!

Answer 1

5) = -3
6) 6·∛3/∛9·∛3 = 6∛3/∛27 = 6∛3/3 = 2∛3

Answer 2

$1) log _{3} \frac{1}{27} =log _{3} 3 ^{-3} =-3log _{3} 3=-3*1=-3$

$2) \frac{6}{ \sqrt[3]{9} } = \frac{6* \sqrt[3]{3} }{ \sqrt[3]{9} * \sqrt[3]{3} } = \frac{6* \sqrt[3]{3} }{ \sqrt[3]{9*3} } = \frac{6 \sqrt[3]{3} }{ \sqrt[3]{27} } = \frac{6 \sqrt[3]{3} }{3} =2 \sqrt[3]{3}$