Question

y=(x-4)*e^(2x-7) найти производную на [2;11]

Answer 1

y`=e^(2x-7)+2(x-4)*e^(2x-7)=e^(2x-7)*(1+2x-8)=e^(2x-7)*(2x-7)=0
2x=7
x=3,5∈[2;11]
y(2)=-2/e³≈-0,1
y(3,5)=-0,5*1=-0,5
y(11)=7*e^15≈2288349