Question

√98- √50+√32 значения вираза

Answer 1

$\sqrt{98}- \sqrt{50}+ \sqrt{32}= \sqrt{2*49}- \sqrt{2*25}+ \sqrt{2*16}=7 \sqrt{2} -5 \sqrt{2} +4 \sqrt{2}$ = $6 \sqrt{2}$

Answer 2

√98−√50+√32=8,48528137
=