Question

Помогите пж!!!
(3x-5)•(4x+7)-(x-8)^2

Answer 1

(3x-5)•(4x+7)-(x-8)²=12x²+21x-20x-35-(x²-16x+64)=12x²+21x-20x-35-x²+16x-64=11x²+17x-99

Answer 2

$(3x-5)(4x+7)-(x-8)^2=12x^2+21x-20x-35-x^2+16x-64= \\ =11x^2+17x-99$