Question

решить неравенство
2x^2-7x>0

Answer 1

x(2x-7)>0
x=0  x=3,5
             +                  _                      +
--------------(0)------------------(3,5)---------------------
x∈(-∞;0) U (3,5;∞)

Answer 2

http://znanija.com/task/12686438

Answer 3

gjvjubnt c 'nbv

Answer 4

помогите с этим)

Answer 5

$2x^2-7x textgreater 0rightarrow 2(x^2- frac{7}{2}x) textgreater 0rightarrow x^2- frac{7}{2}x textgreater 0 \ \ x(x- frac{7}{2}) textgreater 0 \ \ alpha) left { {{x textgreater 0} atop {x textgreater frac{7}{2} }} right. rightarrow xin(3,5;+infty) \ \ beta) left { {{x textless 0} atop {x textless frac{7}{2} }} right. rightarrow xin(-infty;0) \ xin(-infty;0)vee(3,5;+infty)$