Question

(х^2-1)^2+(x-1)^4=0 помогите решить уравнение :)

Answer 1

$(x^2-1)+(x-1)^4=0\\(x-1)(x+1)+(x-1)^4=0\\(x-1)(x+1+(x-1)^3)=0\\(x-1)(x^3-3x^2+4x)=0\\(x-1)cdot xcdot (x^2-3x+4)=0\\x_1=0; ,; ; x_2=1\\x^2-3x+4=0; ,; D=9-16 textless 0; to ; ; x^2-3x+4 textgreater 0; pri; xin R\\Otvet:; x_1=0,; x_2=1.$