Question

2x^2-4=0 решите уравнение

Answer 1

$2x^2-4=0rightarrow x^2-2=0rightarrow (x- sqrt{2})(x+ sqrt{2})=0 \ x+ sqrt{2}=0iff x_1=- sqrt{2} \ x- sqrt{2}=0 iff x_2= sqrt{2}$

Answer 2

Можно короче

Answer 3

флаг в руки...)))

Answer 4

2x² - 4 = 0
D = b² - 4ac = 0² - 4 × 2 × ( - 4) = 0 + 32 = 32
x₁ = 0 + √32 / 2 × 2 = √32 / 4
x₂ = 0 - √ 32 / 2 × 2 = - √ 32 / 4