Question

Решите если не сложно.

Answer 1

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Answer 2

(x³+y³)/(x+y) : (x²-y²) +2y/(x+y)-xy/(x²-y²)=0
1)(x³+y³)/(x+y) : (x²-y²)=(x+y)(x²-xy+y²)/[(x+y)*(x²-y²)]=(x²-xy+y²)/(x²-y²)
2)(x²-xy+y²)/(x-y)(x+y)2y/(x+y)-xy/(x-y)(x+y)=(x²-xy+y²+2xy-2y²-xy)/(x²-y²)=(x²-y²)/(x²-y²)=1
1≠0
Ответ тождество не верное