Question

помогите решить 5y в квадрате -6y+1=0

Answer 1

5y^2 - 6y + 1 = 0
D= 36 - 4 • 5 • 1 = 36 - 20 = 16 = 4^2
y1 = (6 - 4) / 10 = 0.2
y2 = (6+4) / 10 = 1

5y^2 - 6y + 1 = 5(y-0.2)(y-1)