Question

как преобразовать x^{6} [/tex]-y$y {3}$

Answer 1

x⁶-y³=(x²)³-y³=(x²-y)·(x⁴+x²y+y²)
если
x⁶-у·y³=х⁶-у⁴=(х³)²-(у²)²=(x³-y²)·(х³+у²)