Ответы
Ответ дал:
0
Рука уже зудит одно и тоже решать... Куча аналогичных заданий на сервисе.Посмотреть лень ?
![frac{(5^{3})^{6} *5^{-1}}{(5^{4})^{3} *5^{2}} +(0,7)^{0}=frac{5^{18}*5^{-1}}{5^{12}*5^2}+1=frac{5^{17}}{5^{14}}+1=125+1=126 frac{(5^{3})^{6} *5^{-1}}{(5^{4})^{3} *5^{2}} +(0,7)^{0}=frac{5^{18}*5^{-1}}{5^{12}*5^2}+1=frac{5^{17}}{5^{14}}+1=125+1=126](https://tex.z-dn.net/?f=frac%7B%285%5E%7B3%7D%29%5E%7B6%7D+%2A5%5E%7B-1%7D%7D%7B%285%5E%7B4%7D%29%5E%7B3%7D+%2A5%5E%7B2%7D%7D+%2B%280%2C7%29%5E%7B0%7D%3Dfrac%7B5%5E%7B18%7D%2A5%5E%7B-1%7D%7D%7B5%5E%7B12%7D%2A5%5E2%7D%2B1%3Dfrac%7B5%5E%7B17%7D%7D%7B5%5E%7B14%7D%7D%2B1%3D125%2B1%3D126)
![frac{46^{2} -26^{2}}{35^{2} -25^{2}} =frac{20*72}{60*10}=frac{12}{5}=2,4 frac{46^{2} -26^{2}}{35^{2} -25^{2}} =frac{20*72}{60*10}=frac{12}{5}=2,4](https://tex.z-dn.net/?f=frac%7B46%5E%7B2%7D+-26%5E%7B2%7D%7D%7B35%5E%7B2%7D+-25%5E%7B2%7D%7D+%3Dfrac%7B20%2A72%7D%7B60%2A10%7D%3Dfrac%7B12%7D%7B5%7D%3D2%2C4)
![72^{2} -2*72*53+53^{2} =(72-53)^2=19^2=361\\82^{2} +2*82*73+73^{2} =(82+73)^2=155^2=24025 72^{2} -2*72*53+53^{2} =(72-53)^2=19^2=361\\82^{2} +2*82*73+73^{2} =(82+73)^2=155^2=24025](https://tex.z-dn.net/?f=72%5E%7B2%7D+-2%2A72%2A53%2B53%5E%7B2%7D+%3D%2872-53%29%5E2%3D19%5E2%3D361%5C%5C82%5E%7B2%7D+%2B2%2A82%2A73%2B73%5E%7B2%7D+%3D%2882%2B73%29%5E2%3D155%5E2%3D24025)
![frac{a^{2}-ax}{a^{2}x-ax^{2}} - frac{1}{x} =frac{a(a-x)}{ax(a-x)}-frac{1}{x}=frac{1}{x}-frac{1}{x}=0\\ frac{ x^{2} -1}{1-x^{3}} - frac{ x^{2}}{x^{2}-x+1}=frac{(x-1)(x+1)}{(1-x)(1+x+x^2)}- frac{ x^{2}}{x^{2}-x+1}=-frac{x+1}{1+x+x^2}-frac{x^2}{x^2-x+1}=\=frac{-(x+1)(x^2-x+1)-x^2(1+x+x^2)}{(1+x+x^2)(1-x+x^2)}=frac{-(x^4+2x^3+x^2+1)}{1+x^2+x^4} frac{a^{2}-ax}{a^{2}x-ax^{2}} - frac{1}{x} =frac{a(a-x)}{ax(a-x)}-frac{1}{x}=frac{1}{x}-frac{1}{x}=0\\ frac{ x^{2} -1}{1-x^{3}} - frac{ x^{2}}{x^{2}-x+1}=frac{(x-1)(x+1)}{(1-x)(1+x+x^2)}- frac{ x^{2}}{x^{2}-x+1}=-frac{x+1}{1+x+x^2}-frac{x^2}{x^2-x+1}=\=frac{-(x+1)(x^2-x+1)-x^2(1+x+x^2)}{(1+x+x^2)(1-x+x^2)}=frac{-(x^4+2x^3+x^2+1)}{1+x^2+x^4}](https://tex.z-dn.net/?f=+frac%7Ba%5E%7B2%7D-ax%7D%7Ba%5E%7B2%7Dx-ax%5E%7B2%7D%7D+-+frac%7B1%7D%7Bx%7D+%3Dfrac%7Ba%28a-x%29%7D%7Bax%28a-x%29%7D-frac%7B1%7D%7Bx%7D%3Dfrac%7B1%7D%7Bx%7D-frac%7B1%7D%7Bx%7D%3D0%5C%5C+frac%7B+x%5E%7B2%7D+-1%7D%7B1-x%5E%7B3%7D%7D+-+frac%7B+x%5E%7B2%7D%7D%7Bx%5E%7B2%7D-x%2B1%7D%3Dfrac%7B%28x-1%29%28x%2B1%29%7D%7B%281-x%29%281%2Bx%2Bx%5E2%29%7D-+frac%7B+x%5E%7B2%7D%7D%7Bx%5E%7B2%7D-x%2B1%7D%3D-frac%7Bx%2B1%7D%7B1%2Bx%2Bx%5E2%7D-frac%7Bx%5E2%7D%7Bx%5E2-x%2B1%7D%3D%5C%3Dfrac%7B-%28x%2B1%29%28x%5E2-x%2B1%29-x%5E2%281%2Bx%2Bx%5E2%29%7D%7B%281%2Bx%2Bx%5E2%29%281-x%2Bx%5E2%29%7D%3Dfrac%7B-%28x%5E4%2B2x%5E3%2Bx%5E2%2B1%29%7D%7B1%2Bx%5E2%2Bx%5E4%7D)
Вас заинтересует
1 год назад
1 год назад
6 лет назад
6 лет назад
9 лет назад
9 лет назад