Question

$(d^{2} -13) ^{2} -(d-77)^{2} =0$Помогите решить

Answer 1

$(d^2 - 13)^2-(d-77)^2=0 \ \ (d^2-13-(d-77))*(d^2-13+(d-77))=0 \ \ (d^2-d+64)(d^2+d-90)=0 \ \ 1) \ d^2-d+64=0 \ D=1-4*64 textless 0== textgreater net-resh \ \ 2) \ d^2+d-90=0 \ D=1+4*90=361=19^2; \ d _{1} = frac{-1+19}{2}=9; \ d_{2}= frac{-1-19}{2}=-10;$

ОТВЕТ:
- 10; 9