Question

Докажите, пожалуйста

Answer 1

2/(b²+3)-12/(b²+3)(b²-3)+2/(b²-3)=(2b²-6-12+2b²|6)/(b²-3)(b²+3)=
=(4b²-12)/(b²+3)(b²-3)=4(b²-3)/(b²+3)(b²-3)=4/(b²+3)
4>0,b²≥0⇒b²+3≥3⇒4/(b²+3)>0