Question

$sqrt{2} + sqrt{50} - sqrt{32} ;;        sqrt[3]{48} - sqrt[5]{3} - sqrt[2]{7} ;;         sqrt{3}( sqrt{27}+ sqrt[4]{3}$ ;;   

S.O.S

Answer 1

√50=√(25×2)=5√2
√32=√(16×2)=4√2
√2+5√2-4√2=2√2

√27=√(3³)=3^(3/2)
3^(1/2)×3^(3/2)+3^(1/2)×3^(1/4)=3^2+3^(3/4)=9+√ четвертой степени из 27