Question

Помогите решить. Заранее благодарен.

Answer 1

$frac{8m-n}{2n+3} * frac{9+6n}{32m^2-2n^2} = frac{2(4m-n)}{2n+3} * frac{3(2n+3)}{2(16m^2-n^2)} = frac{3(4m-n)}{16m^2-n^2} = frac{3(4m-n)}{(4m+n)(4m-n)} =$ $= frac{3}{4m+n}$