Question

решите уравнение |sin2x|=cosx

Answer 1

|2sinxcosx|=cosx

1) cos x = 0

x=pi/2 + pi*k, k in Integers

2) 2|sin x|=1

4sin^2 x=1

2(1+cos 2x)=1

cos 2x = -1/2

2x = +- 2pi/3 + 2pin

x = +- pi/3 + pi*n, n in Integers