Question

log2(x^2)= 9+ log0.5(x) помогите решить

Answer 1

$log_2{x^2}=9+log_{0,5}x\ log_2{x^2}=9+log_{frac{1}{2}}x\ log_2{x^2}=9+log_{2^{-1}}x\ log_2{x^2}=9-log_2x\ log_2{x^3}=9\ log_2{x^3}=log_22^9\ x^3=2^9\ x=2^3=8$