Question

Для функции f (х) = 3х^2 – х^3 + 2. Найти f(0), f(1), f(-3), f(5).

Answer 1

f(x)=(3x)^2-(x)^3+2 f(0); f(1);f(-3);f(5)
f(0)= 0-0+2= 2
f(1)=(3)^2-(1)^3+2=9-1+2=10
f(-3)=(-9)^2-(-3)^3+2=81+27+2=110
f(5)=(15)^2-(5)^3+2=225-125+2=102