Question

Преобразуйте в многочлен стандартного вида

Answer 1

$21a^{2} -(12a-5+21a^{2})= 21a^{2} -12a+5-21a^{2}=-12a+5 ( x^{2} +x-1)-( x^{2} -x+1)=x^{2} +x-1- x^{2} +x-1=2x-2 -7x^{2} +x+(x+6 x^{2} )=-7x^{2} +x+x+6 x^{2} =- x^{2} +2x (12-5 p^{2} )+( p^{3}+2 p^{2} -p+15)= 12-5 p^{2} + p^{3}+2 p^{2}-p+15=p^{3} - 3p^{2} -p+27$