Question

log2(x-2)+log2(x-3)=1

Answer 1

log2(x-2)+log2(x-3)=1log_2((x-2)(x-3)) = 1
log_2(x^2-5x+6) =1
x^2-5x+6 =2x^2-5x+4 = 0
D = 25-16 = 9
x1 = (5-3)/2 = 1     x2 = (5+3)/2 = 4