Question

log0,5(внизу где логорифм)(3-2х)>-log-0,5 по осн 3

Answer 1

$log_{0.5}(3-2x)>-log_{0.5}3\ log_{0.5}(3-2x)>log_{0.5}frac{1}{3}\ \ 3-2x<frac{1}{3}\ 3-2x>0 \ \ x>frac{4}{3}\ x<frac{3}{2}\ \ (frac{4}{3}; frac{3}{2})$