Question

Найти корни:

1) х(2х+3)(2-х) = 0

2) х + (12/х) = 8

3) 2х³ - 8х = 0

4) (4/х-1) - (4/х+1) = 1

Answer 1

1)x=0 2x+3=0 2-x=0

x=0 x=-3/2 x=2

 

2)x=2 x=6

 

3)x(2x²-8)=0

x=0 2x²-8=0

x=0 x²-4=0

x=0 x=2 x=-2