Question

пи интеграл 0 sin x /3 dx

Answer 1

S₀_π sin(x/3)dx =S₀_π sin((1/3)*xdx=-1:(1/3)*cos(x/3)|₀_π=-3*cos(x/3)|₀_π=-3*(cosπ/3-cos0/3)=-3*(1/2-1)=-3*(-1/2)=3/2=1,5

S₀_π  читать :"интеграл от 0 до π"