Question

(4-3a2)-a2+(7+2a2)-(-2a2+11)=0

Answer 1

$(4-3 a^{2} ) - a^{2} + (7+2 a^{2}) - (-2 a^{2} +11) =0$

4-3a2-a2+7+2a2+2a2-11 =0

0=0

Ответ: x∈R или х∈(-∞; +∞)