Question

Помогитееее !!!!!срочнооооооо!!!!!!!!!

Answer 1

log 1/9√3 = х
осн-е √3
(√3)^x = 1/9√3 = 1/√243=1/(√3)^5=(√3)^-5
x = -5

Answer 2

Решение
log₃¹/² (1/9√3) = 2*log₃¹/² (3⁻⁷/³)¹/² = 2*(-7/6) = - 14/6 = - 2 (1/3)

Answer 3

og₃¹/² (1/9√3) = 2*log₃¹/² [3^(-5/2]¹/² = 2*(-5/20 = - 5

Answer 4

log₃¹/² (1/9√3) = 2*log₃¹/² [3^(-5/2]¹/² = 2*(-5/2) = - 5