Question

Помогите решить 3 примера

Answer 1

(х-4)(х+3)+6 / (х-3)(х+3) = 6/7
(х²+3х-4х-12+6) / (х-3)(х+3) = 6/7
(х²-х-6) / (х-3)(х+3) = 6/7
7(х²-х-6) = 6(х-3)(х+3)
7х²-7х-42 = 6х²-54
х²-7х+12 = 0
Д= 49-4*12*1 = 1
х₁ = (7-1)/2 = 3
х₂ = (7+1) /2 = 4

№3
(х-4)(х+2)+8+(х-8)(х-2) / (х-2)(х+2) = 0
х²+2х-4х-8+8+х²-2х-8х+16=0
2х²-12х+16=0
х²-6х+8=0
Д=36-4*8 = 4
х₁ = (6+2)/2=4
х₂ = (6-2)/2 = 2