Question

решите неравенства 3tg(2x-П/6) √3>=0

Answer 1

-π/3+πn<2x+π/6<π/2+πn
-π/3-π/6+πn<2x<π/2-π/6+πn
-π/2+πn<4x<π/3+πn
-π/8+πn/4<x<π/12+πn/4
x∈(-π/8+πn/4;π/12+πn/4)