Question

Помогите пожалуйста $-frac{4}{3} x^{2} +12=0$
 [tex] -frac{4}{3} x^{2}+28=0

Answer 1

$- frac{4}{3}x^2+12=0\\ frac{4}{3}x^2 =12\\x^2=12: frac{4}{3}\\x^2= frac{12*3}{4}\\x^2=9\\ sqrt{x^2}= sqrt{9}\\x=б3$

$- frac{4}{3}x^2+28=0\\frac{4}{3}x^2=28\\x^2= 28:frac{4}{3}\\x^2= frac{28*3}{4}\\x^2=21\\ sqrt{x^2}= sqrt{21}\\x=б sqrt{21}$

Answer 2

http://znanija.com/task/14931559

Answer 3

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