Question

НАЙДИТЕ КОРНИ УРАВНЕНИЯ
$3t ^{2} +7t+4=0$

Answer 1

3t^2 + 7t + 4 = 0 
D = 7^2 - 4*3*4 = 49 - 48 = 1
t₁ = ( - 7 + 1)/6 = - 6/6 = - 1;
t₂ = ( - 7 - 1)/6 = - 8/6 = - 4/3 = - 1 целая 1/3