Question

(8x+1)(2x-3)-(4x-2)^2=1
решить уравнение

Answer 1

(8x + 1) (2x - 3) - (4x - 2)^2 = 1 
16x^2 - 24x + 2x - 3 - (16x^2 - 16x + 4) - 1 = 0
16x^2 - 22x - 3 - 16x^2 + 16x - 5 = 0 
- 6x - 8 = 0 
- 6x = 8 
x = - 8/6 = - 4/3