Question

2cos4x-4sin(п/2+2x)+3=0

Answer 1

4cos²2x-2-4cos2x+3=0
4cos²2x-4cos2x+1=0
(2cos2x-1)²=0
2cos2x=1
cos2x=1/2
2x=+-π/3+2πn,n∈Z
x=+-π/6+πn,n∈Z