Question

(4 √ 7+ √23)^2-8 √161

Answer 1

1.(4√7+√23)²=(4√7)²+2*4√(7+23)+(√23)²=16*7+8√161+23=112+8√161+23=135+8√161.
2.135+8√161-8√161=135
Ответ:135