Question

(1/7x-1/2y)(0.14-0.7x(2)y)=
(2)- во второй степени

Answer 1

Решение
(1/7x-1/2y)(0.14-0.7x²y) = 1/7x * 14/100 - 1/7x * 7/10 x²y - 1/2y* 14/100 + 
+ 1/2y * 7/10 x²y = 0,2x - 0,1x³y - 0,07y + 0,35x²y²