Question

√4:81-√1:36 Помогите решить

Answer 1

$sqrt{frac{4}{81}}-sqrt{frac{1}{36}}=frac{sqrt{2^2}}{sqrt{9^2}}-frac{sqrt1}{sqrt{6^2}}=frac{2}{9}-frac{1}{6}=\ =frac{4}{18}-frac{3}{18}=frac{1}{18}$