Question

Решите уравнение
х^2 (х+1)-(х+2)(2х-3)=х^2 (х-1)

Answer 1

+x2(x+1)-(x+2)(2x-3)=x2(x-1)
+1x2(1x+1)-(1x+2)(2x-3)=1x2(1x-1)
+1x2(1x+1)-(1x+2)(2x-3)=1x2(1x-1)
(1x3+1x2)-(2x2-3x+4x-6)=(1x3-1x2)
1x3+1x2-2x2+3x-4x+6=1x3-1x2
1x3+1x2-2x2+3x-4x+6=1x3-1x2
1x3-1x2-1x+6=1x3-1x2
-1x=-6
-1x=-6
-1x=-6
1x=6