Question

Помогите разложить на множители
81-(4n+6)²
49-(6d+4)²
(3b³+2)(3b³-2)

Answer 1

81-(4n+6)^2=81-(16n^2+24n+36)=81-16n^2-24n-36
49-(6d+4)^2=49-(36d^2+24d+16)=49-36d^2-24d-16
(3b^3+2)(3b^3-2)=(3b^3)^2-4=3b^6-4