Question

Sin2x = tgx решить уравнение

Answer 1

$sin2x=tgx= frac{sinx}{cosx} \left { {{2sinxcos^2x=sinx} atop {cosx neq 0}} right. = left { {{sinx(2cos^2-1)=0} atop {cosx neq 0}} right. = left { {{sinx*cos2x=0} atop {cosx neq 0}} right. \ sin x =0 \ x = pi n \ cos 2x=0 \2x = frac{ pi }{2} + pi n \x = frac{ pi }{4} + frac{ pi n}{2}$