Question

решите уравнение: 4(n+5/12)=1 целая 1/6 (6n-1 целая 1/7)

Answer 1

$4(n+ frac{5}{12} ) = 1 frac{1}{6} (6n-1 frac{1}{7})$
$4n + frac{5}{3} = frac{7}{6} * 6n - frac{8}{6}$
$4n + frac{5}{3} = 7n - frac{4}{3}$
$3n = frac{5}{3} +frac{4}{3}$ 
$3n = frac{9}{3}$
$3n = 3$
$n = 1$

Answer 2

4(n+5/12)=1 1/6(6n-1 1/7)
4(n+5/12)=7/6(6n-8/7)
4n+20/12=7n-8/6
4n+5/3=7n-4/3
4n-7n=-4/3-5/3
-3n=-9/3
-3n=-3
n=-3:(-3)
n=1